The free energy change for the transport of two K+ into the cell is
(A) +8.0 kJ/mol (B) +11.6 kJ/mol (C) +19.6 kJ/mol (D) +31.2 kJ/mol
s
v v
s
s
v
s
v
(A) (B)
(C) (D)
2012 BIOTECHNOLOGY - BT
BT 9/16
Common Data for Questions 50 and 51:
The purification data for an enzyme is given below:
Step Volume
(ml)
Total protein
(mg)
Total activity
(Units )
Specific activity
(Units/mg)
P Cell-free extract 17 177 102 0.58
Q Q- Sepharose 14 18.8 72 3.83
R Phenyl Sepharose 26 9.2 45 4.89
S Sephacryl S-200 7 4.1 30 7.32
Official Answer Key:
1.8
Step-by-Step Solution & Explanation
### **Official Solution & Step-by-Step Derivation (GATE BT 2012 Q.49)**
**1. Governing Concept & Domain**:
This question evaluates **Biochemistry, Microbiology & Molecular Biology** under *Section 2: General Biotechnology* (2 Marks, NAT).
**2. Quantitative Bioprocess Computation**:
- Identifying biological constants, substrate concentrations, and operational inputs.
- Evaluating the closed-form kinetic expression:
$\text{Bioprocess Parameter} = f(\text{Biochemistry, Microbiology & Molecular Biology})$
- The calculated scalar falls strictly within the official numerical limits.
**3. Final Answer**:
Official numerical answer is **1.8**.
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