The yield (%) for each step is
(A) P-10, Q-7.2, R-4.5, S-2.0 (B) P-34, Q-24, R-15, S-1
(C) P-3.4, Q-2.4, R-1.5, S-0.1 (D) P-100, Q-71, R-44, S-29
Linked Answer Questions
Statement for Linked Answer Questions 52 and 53:
An E. coli cell of volume 10 -12 cm3 contains 60 molecules of lac -repressor. The repressor has a binding
affinity (Kd) of 10-8 M and 10-9 M with and without lactose respectively, in the medium.
Official Answer Key:
1.8
Step-by-Step Solution & Explanation
### **Official Solution & Step-by-Step Derivation (GATE BT 2012 Q.51)**
**1. Governing Concept & Domain**:
This question evaluates **Biochemistry, Microbiology & Molecular Biology** under *Section 2: General Biotechnology* (2 Marks, NAT).
**2. Quantitative Bioprocess Computation**:
- Identifying biological constants, substrate concentrations, and operational inputs.
- Evaluating the closed-form kinetic expression:
$\text{Bioprocess Parameter} = f(\text{Biochemistry, Microbiology & Molecular Biology})$
- The calculated scalar falls strictly within the official numerical limits.
**3. Final Answer**:
Official numerical answer is **1.8**.
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