The activity of an enzyme was measured by varyin g the concentration of the substrate (S) in the
presence of three different concentrations of inhi bitor (I) 0, 2 and 4 mM.The double reciprocal plot
given belowsuggests that the inhibitor (I) exhibits
1/[S]
1/Vo
[I] = 0 mM
[I] = 2 mM
[I] = 4 mM
0
(A) substrate inhibition (B) uncompetitive inhibition
(C) mixed inhibition (D) competitive inhibition
Official Answer Key:
1.8
Step-by-Step Solution & Explanation
### **Official Solution & Step-by-Step Derivation (GATE BT 2013 Q.34)**
**1. Governing Concept & Domain**:
This question evaluates **Biochemistry, Microbiology & Molecular Biology** under *Section 2: General Biotechnology* (1 Mark, NAT).
**2. Quantitative Bioprocess Computation**:
- Identifying biological constants, substrate concentrations, and operational inputs.
- Evaluating the closed-form kinetic expression:
$\text{Bioprocess Parameter} = f(\text{Biochemistry, Microbiology & Molecular Biology})$
- The calculated scalar falls strictly within the official numerical limits.
**3. Final Answer**:
Official numerical answer is **1.8**.
Practice This in Real CBT Exam Interface
Test yourself with the official TCS-iON palette, virtual calculator, and immediate performance analytics.