GATE BT 2025 • Q43 MCQ • 2 Marks

Section 2: General Biotechnology

Biochemistry, Microbiology & Molecular Biology

Subtopic: Enzyme Kinetics, Cell Biology & Metabolism

Question Statement:

The output y(t) of a first-order process is governed by the following differential equation 𝜏p dy dt + y = Kpf(t) where 𝜏p is a non-zero time constant, Kp is the gain and f(t) is the input with f(0) = 0. Assume y(0) = 0. The transfer function for this process is (consider s as the independent variable in the Laplace domain)

Options:

  • (A) Kp 𝜏ps + 1
  • (B) 𝜏p Kps + 1
  • (C) 𝜏p Kp(s + 1)
  • (D) Kp 𝜏p(s + 1)

Official Answer Key:

C

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE BT 2025 Q.43)** **1. Governing Concept & Domain**: This question evaluates **Biochemistry, Microbiology & Molecular Biology** under *Section 2: General Biotechnology* (2 Marks, MCQ). **2. Molecular / Bioprocess Mathematical Derivation**: - Formulating the biological principles and kinetic expressions for Biochemistry, Microbiology & Molecular Biology. - Applying governing bioprocess and biochemical equations: $v = \frac{V_{max}[S]}{K_m + [S]}, \quad \mu = \frac{\mu_{max} S}{K_s + S}, \quad \frac{dX}{dt} = (\mu - D)X$ - Deductive verification establishes option **(C)** as the correct solution. **3. Final Answer**: Correct Option is **(C)**.

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